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@@ -1,208 +0,0 @@
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-import smtplib
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-from email.mime.text import MIMEText
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-from email.header import Header
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-
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-"""
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- 回溯算法(试探法)
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- 在搜索尝试过程中寻找问题的解,当发现已不满足求解条件时,就“回溯”返回,尝试别的路径。回溯法是一种选优搜索法,按选优条件向前搜索,以达到目标。但当探索到某一步时,发现原先选择并不优或达不到目标,就退回一步重新选择,这种走不通就退回再走的技术为回溯法,而满足回溯条件的某个状态的点称为“回溯点”。
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-
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- 回溯算法解决问题的
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- 针对所给问题,定义问题的解空间,它至少包含问题的一个(最优)解。
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- 确定易于搜索的解空间结构,使得能用回溯法方便地搜索整个解空间 。
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- 以深度优先的方式搜索解空间,并且在搜索过程中用剪枝函数避免无效搜索。
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-"""
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-
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-
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-class StockTest(object):
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- """
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- 栈练习
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- """
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-
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- def queen(self, A, cur=0):
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- """
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- 八皇后问题
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- :param A:
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- :param cur:
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- :return:
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- """
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- if cur == len(A):
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- print(A)
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- # return 0
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- else:
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- for col in range(len(A)):
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- A[cur], flag = col, True
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- # 判断当前与之前的所有是否规则冲突
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- for row in range(cur):
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- if A[row] == col or abs(col - A[row]) == cur - row:
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- flag = False
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- break
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- if flag:
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- self.queen(A, cur + 1)
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-
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- def movingCount(self, threshold, rows, cols):
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- "产生 0 矩阵 "
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- board = [[0 for i in range(cols)] for j in range(rows)]
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- global acc
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- acc = 0
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- "下标之和,若大于threshold则TRUE,否则Folse"
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-
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- def block(r, c):
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- s = sum(map(int, str(r) + str(c)))
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- return s > threshold
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-
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- def traverse(r, c):
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- global acc
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- if not (0 <= r < rows and 0 <= c < cols): # 超出角标范围挑出
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- return
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- if board[r][c] != 0: # 不等于0 跳出
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- return
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- if board[r][c] == -1 or block(r, c):
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- board[r][c] = -1 # 超出门限的点记录-1
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- return
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-
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- board[r][c] = 1 # 符合规定的点记录1,并计数加一
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- acc += 1
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- traverse(r + 1, c)
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- traverse(r - 1, c)
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- traverse(r, c + 1)
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- traverse(r, c - 1)
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-
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- traverse(0, 0)
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- return acc
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-
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- def bubble_sort(self, numbers):
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- """
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- 时间复杂度:O(n^2)
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- :param numbers:
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- :return:
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- """
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- n = len(numbers)
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- for i in range(n):
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- for j in range(0, n - i - 1):
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- if numbers[j] > numbers[j + 1]:
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- numbers[j], numbers[j + 1] = numbers[j + 1], numbers[j]
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-
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- return numbers
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-
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- def choose_sort(self, numbers):
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- """
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- 选择排序,时间复杂度O(n^2)
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- :param numbers:
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- :return:
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- """
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- n = len(numbers)
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- for i in range(n):
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- min_index = i
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- min_value = numbers[i]
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- for j in range(i + 1, n):
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- if min_value > numbers[j]:
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- min_value = numbers[j]
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- min_index = j
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- if min_index != i:
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- numbers[min_index] = numbers[i]
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- numbers[i] = min_value
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-
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- return numbers
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-
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- def insert_sort(self, numbers):
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- """
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- 插入排序,时间复杂度O(n^2)
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- :return:
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- """
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- n = len(numbers)
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- for i in range(1, n):
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- insert_index = i - 1
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- insert_value = numbers[i]
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- while insert_index >= 0 and insert_value < numbers[insert_index]:
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- numbers[insert_index + 1] = numbers[insert_index]
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- insert_index -= 1
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- if insert_index + 1 != i:
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- numbers[insert_index + 1] = insert_value
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- return numbers
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-
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- def shell_sort(self, numbers):
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- """
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- 希尔排序,时间复杂度O(n^2)
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- :param numbers:
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- :return:
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- """
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- n = len(numbers)
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- gap = int(n / 2)
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- while gap > 0:
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- for i in range(gap, n):
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- temp = numbers[i]
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- j = i
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- while j >= gap and numbers[j - gap] > temp:
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- numbers[j] = numbers[j - gap]
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- j -= gap
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- numbers[i] = temp
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- gap = int(gap / 2)
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- return numbers
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-
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- def quick_sort(self, numbers):
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- """
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- 快速排序,时间复杂度O(n^2)
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- :param numbers:
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- :return:
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- """
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- if len(numbers) <= 1:
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- return numbers
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- pivot = numbers[int(len(numbers) / 2)]
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- left = [x for x in numbers if x < pivot]
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- middle = [pivot]
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- right = [x for x in numbers if x > pivot]
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- return self.quick_sort(left) + middle + self.quick_sort(right)
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-
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- def merge_sort(self, numbers):
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- """
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- 归并排序
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- :param numbers:
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- :return:
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- """
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-
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- pass
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-
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- def radix_sort(self, numbers):
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- """
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- 基数排序,时间复杂度O(n*k)
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- :param number:
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- :return:
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- """
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- # 记录当前正在排拿一位,最低位为1
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- i = 0
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- max_num = max(numbers)
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- # 记录最大值的位数
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- j = len(str(max_num))
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- while i < j:
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- # 初始化桶数组
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- bucket_list = [[] for _ in range(10)]
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- for x in numbers:
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- # 找到位置放入桶数组
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- bucket_list[int(x / (10 ** i)) % 10].append(x)
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-
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- numbers.clear()
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- # 放回原序列
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- for x in bucket_list:
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- numbers.extend([a for a in x])
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- i += 1
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- return numbers
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-
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- def send_mail(self):
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- sender = '1285211525@qq.com'
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- receivers = '1285211525@qq.com'
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- message = MIMEText('Python 邮件发送测试...', 'plain', 'utf-8')
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- message['From'] = Header('binren')
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- message['To'] = Header('zhangbr')
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- subject = 'test mail'
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- message['Subject'] = Header(subject, 'utf-8')
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- try:
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- stmp_obj = smtplib.SMTP('localhost')
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- stmp_obj.sendmail(sender, receivers, message.as_string())
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- print('send successful')
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- except Exception as e:
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- print(e)
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-
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-if __name__ == '__main__':
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- st = StockTest()
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- nums = [1, 2, 5, 3, 1, 101, 10, 1111, 2]
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- print(st.send_mail())
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